Module: RubyFish::LongestSubstring

Defined in:
lib/rubyfish/longest_substring.rb

Class Method Summary collapse

Class Method Details

.distance(a, b, opts = {}) ⇒ Object



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# File 'lib/rubyfish/longest_substring.rb', line 4

def distance a, b, opts={}
	ignore_case = opts[:ignore_case]
	
  as = a.to_s
  bs = b.to_s
  
  if ignore_case
  	as.downcase!
  	bs.downcase!
  end

  rows = as.size
  cols = bs.size

  if rows == 0 || cols == 0
    return 0
  end

  num= ::RubyFish::MMatrix.new rows, cols
  len,ans=0

  as.each_char.with_index do |ac, i|
    bs.each_char.with_index do |bc, j|
      unless ac == bc
        num[i, j]=0
      else
        (i==0 || j==0)? num[i, j] = 1 : num[i, j] = 1 + num[i-1, j-1]
        len = ans = num[i, j] if num[i, j] > len
      end
    end
  end

  ans
end

.longest_substring(a, b, opts = {}) ⇒ Object



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# File 'lib/rubyfish/longest_substring.rb', line 39

def longest_substring a, b, opts={}
	ignore_case = opts[:ignore_case]
	
  as = a.to_s
  bs = b.to_s
  
  if ignore_case
  	as.downcase!
  	bs.downcase!
  end

  rows = as.size
  cols = bs.size

  res = ""
  len = 0
  last_sub = 0

  if rows == 0 || cols == 0
    return res
  end

  num = ::RubyFish::MMatrix.new rows, cols

  as.each_char.with_index do |ac, i|
    bs.each_char.with_index do |bc, j|
      unless ac == bc
        num[i, j] = 0
      else
        (i == 0 || j == 0)? num[i, j] = 1 : num[i, j] = 1 + num[i-1, j-1]
        if num[i, j] > len
          len = num[i, j]
          this_sub = i
          this_sub -= num[i-1, j-1] unless num[i-1, j-1].nil?
          if last_sub == this_sub
            res += as[i,1]
          else
            last_sub = this_sub
            res = as[last_sub, (i+1) - last_sub]
          end
        end
      end
    end
  end

  res
end

.longest_substring_index(a, b, opts = {}) ⇒ Object



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# File 'lib/rubyfish/longest_substring.rb', line 87

def longest_substring_index(a, b, opts={})
  a.index(longest_substring(a, b, :ignore_case => opts[:ignore_case]))
end