Method: Pay::Subscription.find_by_processor_and_id

Defined in:
app/models/pay/subscription.rb

.find_by_processor_and_id(processor, processor_id) ⇒ Object



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# File 'app/models/pay/subscription.rb', line 53

def self.find_by_processor_and_id(processor, processor_id)
  joins(:customer).find_by(processor_id: processor_id, pay_customers: {processor: processor})
end