Module: Kabal::RussianRules::Declinations

Defined in:
lib/kabal/languages/russian/declinations.rb

Class Method Summary collapse

Class Method Details

.end_with_two_or_three_of_four?(count) ⇒ Boolean

Returns:

  • (Boolean) 


29
30
31
 
# File 'lib/kabal/languages/russian/declinations.rb', line 29

def self.end_with_two_or_three_of_four?(count)
  count.to_s[-1] == "2" or count.to_s[-1] == "3" or count.to_s[-1] == "4"
end

.ends_with_one?(count) ⇒ Boolean

Returns:

  • (Boolean) 


25
26
27
 
# File 'lib/kabal/languages/russian/declinations.rb', line 25

def self.ends_with_one?(count)
  count.to_s[-1] == "1" and (count % 100) / 10 != 1
end

.name_with_declination(number_name, count) ⇒ Object 



4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
 
# File 'lib/kabal/languages/russian/declinations.rb', line 4

def self.name_with_declination(number_name, count)
  #for 5.0e-11 like numbers
  #FIXME find another way to convert number from exp form
  if count.to_s.include? "e"
    count = count.to_s.split('.')[0].to_i
  end
  #FIXME add gem russian
  if number_name[-1, 1] == "а"
    return number_name if ends_with_one? count
    return number_name[0..4] + "и" if end_with_two_or_three_of_four? count
    number_name[0..4]
  elsif number_name[-1, 1] == "я"
    return number_name if ends_with_one? count
    number_name[0..-3] + "ых"
  else
    return number_name if ends_with_one? count
    return number_name + "а" if end_with_two_or_three_of_four? count
    number_name + "ов"
  end
end