Class: Mirah::AST::Condition
- Defined in:
- lib/mirah/ast/flow.rb,
lib/mirah/compiler/flow.rb
Instance Attribute Summary
Attributes inherited from Node
#children, #inferred_type, #newline, #parent, #position
Instance Method Summary collapse
- #compile(compiler, expression) ⇒ Object
- #infer(typer, expression) ⇒ Object
-
#initialize(parent, line_number, &block) ⇒ Condition
constructor
A new instance of Condition.
Methods inherited from Node
#<<, ===, #[], #[]=, #_dump, _load, #_set_parent, child, child_name, #child_nodes, #each, #empty?, #expr?, #inferred_type!, #initialize_copy, #insert, #inspect, #inspect_children, #line_number, #log, #precompile, #resolve_if, #resolved!, #resolved?, #simple_name, #string_value, #temp, #to_s, #top_level?, #validate_child, #validate_children
Constructor Details
#initialize(parent, line_number, &block) ⇒ Condition
Returns a new instance of Condition.
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# File 'lib/mirah/ast/flow.rb', line 21 def initialize(parent, line_number, &block) super(parent, line_number, &block) end |
Instance Method Details
#compile(compiler, expression) ⇒ Object
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# File 'lib/mirah/compiler/flow.rb', line 28 def compile(compiler, expression) # TODO: can a condition ever be an expression? I don't think it can... compiler.line(line_number) predicate.compile(compiler, expression) rescue Exception => ex raise Mirah::InternalCompilerError.wrap(ex, self) end |
#infer(typer, expression) ⇒ Object
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# File 'lib/mirah/ast/flow.rb', line 25 def infer(typer, expression) unless resolved? @inferred_type = typer.infer(predicate, true) if @inferred_type && !@inferred_type.primitive? call = Call.new(parent, position, '!=') do |call| predicate.parent = call [predicate, [Null.new(call, position)]] end self.predicate = call @inferred_type = typer.infer(predicate, true) end @inferred_type ? resolved! : typer.defer(self) end @inferred_type end |